Hi, here's a fast overview of Roulette Bingo Event. This post is only to help you decide whether or not you want to put effort into the event.
( Not going to explain the whole event, read the main post for that )
How many coins can you get a day? 53.
How many coins can i get from just logging in daily? 100.
How many coins does it take on average to finish a board? 95ish
Maximum # of coins obtainable: 1060 (Actually less, because of maintenance)
Can I get a squirrel bag without afking? If your lucky.
Bingo = chance of coupon fragment for detective squirrel bag.
Full Bingo = 1 coupon fragment for detective squirrel bag.
Is the bag coupon tradable? Yes.
Is the bag coupon fragment tradable? Yes.
Is the bag tradable? No, only drop tradable.
Example Simulation (28 of 20000 trials exceeded 255 coins and were cut out to shrink plot)
This graph should give you a better idea of how many coins you may end up using to complete a board.
Edit: This is a simulation table, Left is the # of occurrences, Bottom is # of Bingo Coins used to fill Board.
Edit 2: More numbers because hot-time free stamps:
How many coins to get 24 unique numbers? 70ish <- ideal for maximizing benefit of the free stamps
How many coins to get 23 unique numbers? 58ish <- ideal for bag (assuming you get no coupon piecesfrom normal bingo)
How many coins to get 22 unique numbers? 49ish
How many coins to get 21 unique numbers? 43ish
How many coins to get 20 unique numbers? 38ish
How many coins to get 20 unique numbers? 34ish
(Since you only get 6 free stamps, if you just want to get the bag its probably ideal to strive for 2 remaining stamps before using the hottime free stamps)
Comments
Event is 20 days long.
5*20 = 100.
Nice work though. Very helpful
Ask a few day which number is giving them trouble on the bingo board. If you find that everyone is having different numbers that they cant get, then its probably uniform probability.
Also it's not like this is a gacha, there is probably no "S" tier number :^)
Formula: E(n) = n * sum(i, n, (1/n))
Therefore to get all 25 just via coins: ~95.40
24: ~90.62
so you save about 5 coins, on average.
EDIT: Actually I got the math wrong, I made the incorrect assumption that you would be trying to get a new number out of a smaller total possibility range. Therefore, if you were to work numbers out, you would probably save more than 5 because you have a greater chance of repeating numbers than my incorrect assumption.
The formula is summation of (25/n)^-1 from 1 to 25. which is 95.4
and for 24 numbers, same formula but from 2 to 25, or ~70.4.
This makes sense because when your down to your last number you can expect a 1/25 chance to get your last number, thus you should average 25 coins to get the last number
Found out the coins only stack to 50 but yeah i think i've used 113 or so just to get the number 6. and nothing still.
How strange, every board I've been filling, 6 has been the last number to fill. Also where do you live, I graduated high school with a joey bahn.
I only got about 170 coins total.
I'd say yes since someone figured out it was 100 coins average per board. Enjoy your squirrel.